35x^2y^4/42x^4y^-5 - solution

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Solution for 35x^2y^4/42x^4y^-5 equation:

x in (-oo:+oo)

x^4*((35*x^2*y^4)/42)*y^-5 = 0

5/6*x^6*y^-1 = 0 // : 5/6*y^-1

x^6 = 0

x = 0

x = 0

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